d0
1.8α=d/d00.139d
0.25b0
0.8β=b0/b 0.320b
2.5K1=
(α^2+β*(1-α^2))/(2*(α+β(1-α))0.402K2=
1/((α^3+β*(1-α)^3)/12+α*(K1-α/2)^2+β*(1-α)*((1+α)/2-K1)^2)24.791y0=
K1*d00.723I=b*d0^3/K20.588
T型截面形心及惯性矩系数